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In a triangle ABC,
sinA - cosB - cosC = 0.
What is angle B equal to ?
π/6
π/4
π/3
π/2
To solve the problem, let's consider some basic trigonometric identities and relationships within a triangle:
- We know in a triangle ABC, the angles sum up to p: A + B + C = p.
- Given the equation: sinA - cosB - cosC = 0.
Let's analyze the options, knowing sinA = cos(p/2 - A):
- Option 1: p/6
- For B = p/6, cosB = v3/2. Check if sinA = cosB + cosC holds.
- Option 2: p/4
- For B = p/4, cosB = v2/2. Check if sinA = cosB + cosC holds.
- Option 3: p/3
- For B = p/3, cosB = 1/2. Check if sinA = cosB + cosC holds.
- Option 4: p/2
- For B = p/2, cosB = 0. Check if sinA = cosB + cosC holds.
- If B = p/2, A + C = p/2; thus, sinA = cosC, and the equation is balanced: sinA - 0 - cosC = sinA - cosC = 0.
- Correct Answer: p/2
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