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If a, b, c are in GP where a > 0, b > 0, c > 0, then which of the following are correct ?
1. a2, b2, c2 are in GP
2. 1/a, 1/b' 1/care m GP
3. √a, √b , √c are in GP
Select the correct answer using the code given below :
1 and 2 only
2 and 3 only
1 and 3 only
1, 2 and 3
- If \( a, b, c \) are in GP, then \( b = ar \) and \( c = ar^2 \) for some common ratio \( r \).
- Statement 1: \( a^2, b^2, c^2 \) can be shown as \( (ar)^2, (ar^2)^2 \), and it follows the pattern of a GP with the same common ratio.
- Statement 2: \( \frac{1}{a}, \frac{1}{b}, \frac{1}{c} \) will also be in GP since inverses of terms in GP still form a GP.
- Statement 3: \( \sqrt{a}, \sqrt{b}, \sqrt{c} \) are in GP because roots of GP terms follow a pattern similar to the original sequence.
The correct answer is Option 4: 1, 2, and 3.
By: Parvesh Mehta ProfileResourcesReport error
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