send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
From a Circular metal plate of radius 7 cm and thickness 0•16 mm, a sector is cut off containing an angle 150°. The remaining piece is moulded into a spherical bead of radius r. What is the value of r in cm ?
0.35
0.7
1.05
1.4
Correct option 2: 0.7 cm
Given:
Radius of circular plate (R) = 7 cm
Thickness of plate (h) = 0.16 mm = 0.016 cm
Angle of the sector (θ) = 150°
Concept:
The volume of the remaining piece after cutting the sector is equal to the volume of the spherical bead formed. Formula used:
Volume of the sector of a cylinder = ( θ/360) π R2h
Volume of the sphere = (4/3) π r3
Solution:
Volume of the sector cut off:
=> (150/360) × π x(7)2 × 0.016
=> (5/12) × π x 49 × 0.016
=> 1.026 cm3
Volume of the remaining piece:
=> Total volume of the plate - Volume of the sector cut off
=> π x R2xh-1.026
=>? × 49 × 0.016 - 1.026
=> 3.14 × 0.784 - 1.026
=>2.46176-1.026
=> 1.43576 cm3
Volume of the spherical bead: => (4/3)π r3= 1.43576
=> r3 = (1.43576 × 3)/(4xπ)
=> r3 = 0.3427 cm3 = 0.343 cm3
=> r = 3√0.343
=> r = 0.7 cm
.. The value of r is 0.7 cm.
By: Parvesh Mehta ProfileResourcesReport error
Access to prime resources
New Courses