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A bottle contains spirit and water in the ratio 1 : 4 and another identical bottle contains spirit and water in the ratio 4 : 1. In what ratio should the mixtures in the two bottles be mixed to get a new mixture in which the ratio of spirit to water is 1 : 3 ?
5 : 1
6: 1
10 : 1
11 : 1
Let's break down the question systematically:
- The first bottle has spirit : water = 1 : 4
? Spirit fraction = 1/5, Water fraction = 4/5
- The second bottle has spirit : water = 4 : 1
? Spirit fraction = 4/5, Water fraction = 1/5
- We want to mix them to get spirit : water = 1 : 3
? Spirit fraction in new mix = 1/4, Water fraction = 3/4
Now, let the two bottles be mixed in x : y ratio.
- Amount of spirit in mix = x(1/5) + y(4/5)
- Amount of water in mix = x(4/5) + y(1/5)
- Ratio required: spirit : water = 1/3
Set up the equation:
$$\frac{x(1/5) + y(4/5)}{x(4/5) + y(1/5)} = \frac{1}{3}$$
Cross-multiplied and simplified:
- numerator: x + 4y
- denominator: 4x + y
So,
$$
\frac{x + 4y}{4x + y} = \frac{1}{3}
Cross multiply:
3(x + 4y) = 4x + y \implies 3x + 12y = 4x + y \implies 12y - y = 4x - 3x \implies 11y = x
So, the bottles should be mixed in a 1 : 11 ratio (x : y = 1 : 11, or y : x = 11 : 1).
Let's check the options:
- Option 1: 5 : 1
- Option 2: 6 : 1
- Option 3: 10 : 1
- Option 4: 11 : 1
The correct answer is Option 4: 11 : 1
By: Parvesh Mehta ProfileResourcesReport error
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