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- Let's define the two numbers as \( x \) and \( y \).
- Their sum is given by \( x + y = 40 \).
- The arithmetic mean (AM) is \( \frac{x + y}{2} = 20 \).
- The geometric mean (GM) is \( \sqrt{xy} \).
- We know GM is 20% less than AM:
$$
\sqrt{xy} = 0.8 \times 20 = 16
- So, \( xy = 16^2 = 256 \).
- These lead us to the quadratic equation:
t^2 - 40t + 256 = 0
- Solving this, \( t = \frac{40 \pm \sqrt{40^2 - 4 \times 256}}{2} \).
- This solves to \( t = 32 \) or \( t = 8 \) leading to numbers 32 and 8.
- Difference: \( 32 - 8 = 24 \).
- ? Option 3 - 24 is correct.
.
By: Parvesh Mehta ProfileResourcesReport error
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