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A, B, C, D can complete a work in 3, 6, 9, 12 hours respectively. Further, only one person can work at a time in each hour and nobody can work for two consecutive hours. It is not necessary to engage all. What is the minimum number of hours that they will take to finish the work ?
36/25
12/5
4
2
Let's break down the options and explain the scenario:
- A can do the work in 3 hours, so A's rate = 1/3 per hour.
- B in 6 hours: B's rate = 1/6 per hour.
- C in 9 hours: C's rate = 1/9 per hour.
- D in 12 hours: D's rate = 1/12 per hour.
- Only one person at a time, and not in consecutive hours.
- We want the minimum hours to finish the work.
Optimal way:
- Alternate the two fastest workers: A and B, as using A for 1 hour, then B for 1 hour, then again A, and so on.
- For 2 hours: Work done = (1/3 + 1/6) = 1/2.
- For 4 hours (two cycles): Work done = 2 × (1/3 + 1/6) = 1 whole work.
So, minimum number of hours is 4.
Options Analysis:
- Option 1 (36/25) ˜ 1.44 hours: Impossible as nobody can finish that fast given constraints.
- Option 2 (12/5) = 2.4 hours: Again not possible under the rules.
- Option 3 (4): Matches our calculation.
- Option 4 (2): Too short, not enough work can be done.
Correct Answer: Option 3 (4 hours)
By: Parvesh Mehta ProfileResourcesReport error
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