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If the length of a rectangle is increased by 66 2/3% then bar what percent should the width of the rectangle be decreased in order to maintain the same area ?
50%
45%
40%
35%
- Initial Setup: Let's assume the initial length (L) and width (W) of the rectangle. The area is given by Area = L × W.
- Length Increase: The length is increased by 66 2/3%, which is equivalent to multiplying the original length by 5/3. So, the new length is 5L/3.
- Maintain Same Area: To keep the area constant, let the new width be W'. Thus, (5L/3) × W' = L × W.
- Solve for New Width: W' = (L × W) / (5L/3) = 3W/5.
- Width Decrease: The width decreases from W to 3W/5. The percentage decrease is calculated as ((W - 3W/5)/W) × 100% = 2/5 × 100% = 40%.
Correct Option: 3 - 40%
By: Parvesh Mehta ProfileResourcesReport error
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