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A solid cube is cut into two cuboids of equal volume. What is the ratio of total surface area of the given cube to that of one of the cuboids ?
2 : 1
3 : 2
4 : 3
5 : 3
Let’s break it down:
- Suppose the original cube has side \( a \).
- Its volume is \( a^{3} \). Cut it in half, so each cuboid has volume \( \frac{a^{3}}{2} \).
- The simplest way: cut along a plane parallel to a face. Each cuboid is then \( a \times a \times \frac{a}{2} \).
- Surface area of the original cube: \( 6a^{2} \).
- Surface area of one cuboid: Two faces are \( a \times a \), four are \( a \times \frac{a}{2} \). So,
\( 2(a^2) + 4(a \cdot \frac{a}{2}) = 2a^2 + 2a^2 = 4a^2 \).
- So the ratio \( \frac{6a^2}{4a^2} = \frac{3}{2} \) or 3 : 2.
Let’s look at the options:
- Option 1: 2 : 1 —— Not matching.
- Option 2: 3 : 2 —— This matches our answer.
- Option 3: 4 : 3 —— Doesn't match.
- Option 4: 5 : 3 —— Nope.
By: Parvesh Mehta ProfileResourcesReport error
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