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OABC is a rhombua whoae three vertices lie on a circle with centre at O. If the area of the rhombus is 32?3 aquare cm, then what ia the radius of the circle ?
4 cm
6 cm
8 cm
16 cm
- A rhombus is a quadrilateral with all sides equal and opposite angles equal.
- In rhombus OABC, vertices O, A, and B lie on a circle with the center at O.
- Since O is the center and a vertex, the radius is the distance from O to any vertex on the circle.
- The rhombus's area is given as \( 32\sqrt{3} \) square cm.
- The formula for the area of a rhombus is \(\frac{1}{2} \times \text{product of diagonals}\).
- Since O is the center, each diagonal is the diameter of the circle.
- Calculate using \( \frac{1}{2} \times 2r \times 2r = 32\sqrt{3} \) to find the circle's radius \( r \).
- Solving, \( r^2 \sqrt{3} = 32\sqrt{3} \), gives \( r^2 = 32 \).
- Therefore, r = 8 cm.
- From the given options:
- Option 1: 4 cm
- Option 2: 6 cm
- Option 3: 8 cm \(\huge\checkmark\)
- Option 4: 16 cm
-
By: Parvesh Mehta ProfileResourcesReport error
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