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A slower train is passed by a faster one in 72 seconds. The faster train has a length twice that of the slower one. They are running on parallel tracks. Their speeds are 28 m/s and 144 km/hr respectively. What is length of the faster train?
288 m
278 m
556 m
576 m
None of these
- First, convert the speed of the faster train from kilometers per hour to meters per second: \(144 \, \text{km/hr} = 40 \, \text{m/s}\).
- The relative speed between the two trains: \(40 \, \text{m/s} - 28 \, \text{m/s} = 12 \, \text{m/s}\).
- If the faster train passes the slower one in 72 seconds, the relative distance covered (i.e., the total length of both trains) is: \(12 \, \text{m/s} \times 72 \, \text{s} = 864 \, \text{m}\).
- Let \( L \) be the length of the slower train. Then the length of the faster train is \( 2L \).
- The equation: \( L + 2L = 864 \).
- Solving, \( 3L = 864 \) leads to \( L = 288 \).
- Thus, the faster train is \( 2 \times 288 = 576 \, \text{m} \) long.
- Answer: Option 4 - 576 m
By: Parvesh Mehta ProfileResourcesReport error
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