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The ratio of the incomes of two employees is 7 : 4, and the ratio of their expenditures is 3 : 1. If each of them manages to save Rs.4,800 per month, find the sum of their monthly incomes (in Rs.).
21120
20120
21150
18150
- Let the incomes of the two employees be 7x and 4x.
- Let their expenditures be 3y and y.
- Savings for both: Income - Expenditure = 4,800.
- For the first employee: 7x−3y=4,800.
- For the second employee: 4x−y=4,800.
- Solving the two equations:
- From 4x−y=4,800, we get y=4x−4,800.
- Substitute y=4x−4,800 in 7x−3y=4,800.
- Solve for x to find the values.
Correct calculations give the solution:
- Total income = 7x+4x=11x.
- Calculated x gives a correct monthly total income of: ?21,120.
- This corresponds to Option 1: 21,120.
The correct answer is Option 1: 21,120.
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