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The simple interest earned on Rs.2,800 at a rate of 10% per annum for 3 years is Rs.x and Rs.1,736 is the simple interest earned on Rs.6,200 at a rate of 14% for y years, then the value of x/y is:
140
380
550
420
- To find the simple interest \( x \) for the first case, use the formula: $$ SI = \frac{{P \times R \times T}}{100} $$
- Principal \( (P) = 2800 \)
- Rate \( (R) = 10\% \)
- Time \( (T) = 3 \text{ years} \)
- $$ x = \frac{{2800 \times 10 \times 3}}{100} = 840 $$
- For the second scenario, you're given:
- Simple interest \( SI = 1736 \)
- Principal \( (P) = 6200 \)
- Rate \( (R) = 14\% \)
- Need to find time \( (y) \)
- $$ 1736 = \frac{{6200 \times 14 \times y}}{100} $$
- Rearrange to find \( y \): $$ y = \frac{{1736 \times 100}}{6200 \times 14} \approx 2 $$
- Finally, calculate the ratio \(\frac{x}{y}\):
- \(\frac{840}{2} = 420\)
- Option 4 (420) is correct.
By: Parvesh Mehta ProfileResourcesReport error
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