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The number of products sold by A in 2015 is 1.5 times of the number of products sold by B in that year. Number of Products sold by A in 2017 is 14 more than that in 2015. In 2016 A sold 10% less products as compared to 2017. The Ratio of number of products sold by B in 2015 to that in 2017 is 3: 8. Total number of products sold by B in all the three years is 1 less than the number of products sold by A and B together in 2017. The number of products sold by B in 2016 is 1 more than that sold by it in 2015.
If the number of products sold by C in 2017 is 25% more than the number of products sold by A in 2015, then find the sum of number of products sold by C in 2017 and that by B in 2016.
92
104
1101
112
70
- Let's assume B sold \( x \) products in 2015.
- Then A sold \( 1.5x \) in 2015.
- In 2017, A sold \( 1.5x + 14 \).
- In 2016, A sold 10% less than 2017, i.e., \( 0.9 \times (1.5x + 14) \).
- The ratio of B's 2015 to 2017 sales is 3:8, thus B sold \( \frac{8x}{3} \) in 2017.
- In 2016, B sold \( x + 1 \).
- B's total sales for all years are: \( x + (x + 1) + \frac{8x}{3} \).
- A and B together sold \( 1.5x + 14 + \frac{8x}{3} \) in 2017.
- B's total = A and B's 2017 total - 1.
- C's 2017 sales = 25% more than A's 2015 = \( 1.25 \times 1.5x \).
- Sum needed: C's 2017 sales + B's 2016.
Let's solve these:
- B's 2015: \( x \), B's 2017: \( \frac{8x}{3} \), B's 2016: \( x + 1 \).
- A + B 2017: \( 1.5x + 14 + \frac{8x}{3} \).
- \( \frac{11x}{3} + 14 = x + (x + 1) + \frac{8x}{3} + 15 \).
- Find correct \( x \).
Calculating sales number and comparing the options provides us with:
Option 5: 70 is correct.
By: Parvesh Mehta ProfileResourcesReport error
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