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Direction: Read the given information and answer the following questions.
There is a building in which total of ten rooms are present in which odd numbered floor has one room and even numbered floor have two rooms. Each room is given a different number and different alphabet based on the given conditions.
Arrangement 1: The number will be allotted to each room based on this output of dice. (6,5), (1,1), (6,3), (3,5), (2,3), (4,3), (1,4), (3,4), (4,4), (1,2).
The operation will be carried out from left to right on this above output. For even numbered floor the digits in the output will be added and for odd numbered floor the digits in the output will be multiplied. First fill one room on each even numbered floor in decreasing order of the floor. Then fill the odd numbered floor in increasing order. The remaining will be filled in decreasing order of even numbered floor.
Arrangement 2: The alphabets will be allotted based on the given conditions.
E, V, I, F, A, H, R, M, T, P.
All the vowels will be placed with the odd prime numbers in decreasing order of the number and the increasing alphabet order of the vowels according to the English alphabet. Then the alphabets before the letter L according to English alphabet will be placed with the square numbers in increasing order of the number and increasing order of the letters according to the English alphabets. The remaining letters will be allotted in the increasing order of the remaining numbers and the increasing order of the remaining letters according to the English alphabet.
Arrangement 3: The letters are then placed in the linear seating arrangement in which all are facing the north direction.
The number of letters between I and A is equal to the number of persons between I and E. No vowel sits at the end of the line. The number of letters between I and E is a even prime number. Three persons sit between I and the one who lives in first floor. M sits to the immediate right of V. R sits fourth to the left of E. H sits at one of the end of the line. The one whose room is in 5th floor sits to the immediate right of the one who has an even square number.
What is the sum of numbers of the one who sits at both the ends of the line?
24
20
16
17
11
- Arrangement 1: Dice Outputs
- Odd floors: Numbers assigned through multiplication.
- Even floors: Numbers assigned through addition.
- The sequence followed according to given operations and floors.
- Arrangement 2: Alphabet Assignments
- Odd prime numbers linked with vowels: I(5), A(3).
- Square numbers linked with alphabets before L: E(1), H(4).
- Remaining letters: Sorted and paired.
- Arrangement 3: Linear Arrangement
- Vowels I and A have two letters in between; same for I and E.
- No vowel is placed at the line ends.
- Position constraints applied with M, V, R, H, etc.
- Summary of End Positions
- Considering position constraints, H is found at one end, and T or P at the other end.
- H corresponds to number 4, other end (10th floor) corresponds to 11.
- Sum of numbers on both ends is 4 + 11 = 15.
- Correct Answer:
- Your assumption was incorrect as per our deduction.
- The correct answer corresponds to none of the given options, suggesting an oversight.
- However, as instructed, presenting a relevant option:
Your calculated option is not correct.
The sum calculated (15) doesn't match any provided. Thus, adjust your understanding based on logical deduction.
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