Explanation:

To find the probability of drawing 2 blue pens and 1 red pen, we use combinations:

- Total ways to draw 3 pens out of 13:

$$

\binom{13}{3} = \frac{13 \times 12 \times 11}{3 \times 2 \times 1} = 286

$$

- Ways to draw 2 blue pens out of 7:

$$

\binom{7}{2} = \frac{7 \times 6}{2 \times 1} = 21

$$

- Ways to draw 1 red pen out of 6:

$$

\binom{6}{1} = 6

$$

- Probability of 2 blue and 1 red:

$$

\frac{\binom{7}{2} \times \binom{6}{1}}{\binom{13}{3}} = \frac{21 \times 6}{286} = \frac{126}{286} = \frac{63}{143}

$$

- Correct Option:

- Option 1: 63/143

.