A man is running 400 m ahead of an engine of length 100m with a speed of 5 m s If the speed of the t...........

Quantitative Aptitude (SBI-PO) Time & distance

A man is running 400 m ahead of an engine of length 100m with a speed of 5 m/s. If the speed of the train in the same direction is 25 m/s, find in how much time the train will cross the man?

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SBI PO Prelims

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25 sec

22 sec

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Explanation:

- The distance between the man and the start of the train is initially 400 meters.

- The train needs to travel this 400 meters plus its own length of 100 meters, so a total of 500 meters, to completely pass the man.

- The relative speed of the train with respect to the man is the difference in their speeds: \(25 \, \text{m/s} - 5 \, \text{m/s} = 20 \, \text{m/s}\).

- Time taken to cross the man is calculated using the formula: \(\text{Time} = \frac{\text{Distance}}{\text{Relative Speed}} = \frac{500 \, \text{m}}{20 \, \text{m/s}} = 25 \, \text{seconds}\).

- ?? Correct Answer: Option 1 - 25 sec