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Two inlet Pipes A and B can fill the tank in 3 hours. C is the outlet Pipe. Together A, B and C can fill the tank in 4 hours. Find in how many hours, Pipe C can emptied the tank.
8 hours
9 hours
15 hours
10 hours
12 hours
- Given, pipes A and B together fill the tank in 3 hours. This means their combined rate is 1/3 of the tank per hour.
- All three pipes, A, B, and C, fill the tank in 4 hours. Thus, their combined rate is 1/4 of the tank per hour.
- Let the rate at which Pipe C empties the tank be 1/x of the tank per hour.
- The combined rate of A and B is 1/3, and the rate of A, B, and C is 1/4, so we have:
$$
\frac{1}{3} - \frac{1}{x} = \frac{1}{4}
- Solving for x:
\frac{1}{x} = \frac{1}{3} - \frac{1}{4} = \frac{4-3}{12} = \frac{1}{12}
- Therefore, x = 12. Pipe C can empty the tank in 12 hours.
By: Parvesh Mehta ProfileResourcesReport error
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