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Two pipes A and B can fill a tank in 18 minutes and 24 minutes respectively. If both the pipes are opened simultaneously, then after
how much time should pipe B be closed so that the tank is full in 12 minutes?
6 minutes
9 minutes
8 minutes
5 minutes
- Pipe A can fill the tank in 18 minutes, so it fills 1/18 of the tank per minute.
- Pipe B can fill the tank in 24 minutes, so it fills 1/24 of the tank per minute.
- Together, they fill \( \left(\frac{1}{18} + \frac{1}{24}\right) \) of the tank per minute.
- This simplifies to \(\frac{4 + 3}{72} = \frac{7}{72}\).
- They need to fill the tank in 12 minutes.
- In 12 minutes, both pipes together fill \( \left(\frac{7}{72} \times 12\right) = \frac{7}{6}\) of the tank if kept open.
- But for full tank, they should fill 1 tank =
=>\( \frac{7}{72} * b + \frac{12-b}{18} = 1\)
\(b=8\)
- Option:3 - 8 minutes is the time after which pipe B should be closed.
Correct Answer: Option 3 - 8 minutes
By: santosh ProfileResourcesReport error
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