The angle of elevation ofthe top of a tree from a point on the ground which is 300 m away from thetr...........

Quantitative Aptitude (CPO) Height and Distance

The angle of elevation ofthe top of a tree from a point on the ground which is 300 m away from thetree is 30^o When the tree

grew up, its angle ofelevation ofthe top of it became 60^o from the same point. How much did the tree grow? (nearest to an

integer)

This questions was previously asked in

SSC CPO 12th Dec 2019 Shift-2

342 m

364 m

384 m

346 m

Let’s break it down:

- The point is 300?m from the base of the tree.

- At first, the angle of elevation to the top is 30°.

- From basic trigonometry: tan?30° = height/300 ? height1 = 300 × (1/v3) ˜ 173?m

- After the tree grows, same point, angle is now 60°.

- tan?60° = height/300 ? height2 = 300 × v3 ˜ 519.6?m

- The tree’s growth = height2 – height1 ˜ 519.6 – 173 = 346.6?m

Now, the options:

- 342?m (a little short),

- 364?m (too high),

- 384?m (way high),

- 346?m (right on target)

What this really means is: Option 4, 346?m, is the correct answer.

Submit Error