Explanation:

For divisibility by $$6 = 3\times 2 $$
the number must be even and sum of digit must be divisibility = 3
the check option (A) 4325672
4+3+2+5+6+7+2 = 29
it is not divisibile by 3
check (B) 5643252
sum fo given digit 5+6+4+3+2+5+2 = 27 it is divisible by 3 and hence it divisible by also 6
check option (C)96543111
sum of given digit 9+6+5+4+3+1+1+1 = 31 it is odd not divisible by 6
check option (D) 465466
sum of given digit 4+6+5+4+6+6 = 31 it is not divisible by 6
therefore Only Option (B)5643252 is divisible by 6
hence Option (C)5643252 Ans