send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
If r is the remainder when each of 4749, 5601 and 7092 is divided by the greatest possible number d(>1), then the value of (d + r) will be:
276
271
298
282
Correct Option is 1: 276
Solution
As we know 5601 -4749 = 852
7092 - 5601 = 1491
Now HCF of 852 and 1491 is d = 213.
Now divding 4749 by 213 gives remainder = 63.
Sum od (d +r)= 213+63 = 276
Report error
Access to prime resources