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An earthworm of length 18 cm is crawling along a certain path with a speed of 4 cm/s. An insect overtakes the earthworm in 6
s. How fast (in cm/s) is the insect walking? Assume that they both are walking along parallel paths.
7.0
6.5
5.5
6.0
- The earthworm is 18 cm long and moves at 4 cm/s.
- The insect overtakes (i.e., covers the full length of the earthworm) in 6 seconds.
- In 6 seconds, the earthworm moves 4 x 6 = 24 cm.
- To overtake, the insect must cover the 18 cm length of the worm in addition to whatever the earthworm has moved in these 6 seconds, i.e., 18 cm + 24 cm = 42 cm.
- So, the speed of the insect = 42 cm / 6 s = 7 cm/s.
Option:1, 7.0 cm/s is correct.
By: santosh ProfileResourcesReport error
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