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An earthworm of length 18 cm is crawling along a certain path with a speed of 4 cm/s. An insect overtakes the earthworm in 6
s. How fast (in cm/s) is the insect walking? Assume that they both are walking along parallel paths.
7.0
6.5
5.5
6.0
- The earthworm is moving at a speed of 4 cm/s.
- The insect overtakes the earthworm in 6 seconds.
- To find the insect's speed, calculate how much further it travels in those 6 seconds.
- During 6 seconds, the earthworm covers 4cm/s×6s=24cm.
- The insect must cover at least 24 cm more than the earthworm to overtake it.
- Insect's relative speed: 24cm6s=4cm/s.
- Total insect speed: 4cm/s+4cm/s=8cm/s.
- Correct Answer: None of the provided options are accurate.
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