Explanation:

- The train is 338 meters long and travels at a speed of 60 km/h.

- The train crosses the man in 39 seconds.

- Convert the train's speed to meters per second: \(60 \, \text{km/h} = 60 \times \frac{1000}{3600} \, \text{m/s} = 16.67 \, \text{m/s}\).

- The train and the man are moving in the same direction.

- Relative speed required to cross the man: \(\text{Train length}/ \text{Time} = 338 \, \text{m} / 39 \, \text{s} \approx 8.67 \, \text{m/s}\).

- Train's speed minus man's speed equals relative speed: \(16.67 - \text{Man's speed} = 8.67\).

- Calculate man's speed: \(16.67 - 8.67 = 8 \, \text{m/s}\).

- Correct answer is Option 3: \(8 \, \text{m/s}