Multiple Choice Questions

Pipes A and B can fill a tank in 15 hours and 12 hours respectively Pipe C alone can empty the full ...........

Quantitative Aptitude (MTS) Pipes&cistern

Pipes A and B can fill a tank in 15 hours and 12 hours, respectively. Pipe C alone can empty the full tank in 10 hours. If all the

three pipes are opened together for 2 hours 40 minutes, then what part of the tank will remain unfilled?

This questions was previously asked in

SSC MTS 14th October 2021 Shift-2

3/20

13/15

2/15

17/20

- Pipe A fills 1/15 of the tank in an hour.

- Pipe B fills 1/12 of the tank in an hour.

- Pipe C empties 1/10 of the tank in an hour.

- The combined rate of all pipes in an hour is (1/15 + 1/12 - 1/10).

- This simplifies to (4 + 5 - 6)/60 = 3/60 = 1/20 of the tank per hour.

- In 2 hours and 40 minutes (or 8/3 hours), they fill (8/3) * (1/20) = 8/60 = 2/15 of the tank.

- Therefore, the unfilled part of the tank is 1 - 2/15 = 13/15.

- Option: 2, 13/15 is the correct answer.

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