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In a certain code language, 'FORT' is written as '6301820' and 'PRICE' is written as
'161818310'. How will 'FUTILE' be written in that language?
64220091205
64220181210
62120091210
62220181310
Alright, let's break it down:
- In the code language:
- FORT ? 6301820:
- F=6, O=30, R=18, T=20
- PRICE ? 161818310:
- P=16, R=18, I=18, C=3, E=10
- It looks like each letter is replaced with its position in the alphabet, then multiplied by 2. (F=6, 6x2=12? Wait, no. Let's check further.)
- Actually, F is the 6th letter, and O is the 15th (but coded as 30, which is 15x2). R is 18 (just as in the alphabet), and T is 20. Hmm. For PRICE: P is 16 (alphabet 16), R is 18, I is 18 (but actual alphabet is 9, so 9x2=18), C is 3, E is 10 (actually 5, so 5x2=10).
- So, the pattern is:
- Vowels: Letter position x 2
- Consonants: Letter position as is
Now, for FUTILE:
- F (consonant): 6
- U (vowel): U=21, 21x2=42
- T (consonant): 20
- I (vowel): I=9, 9x2=18
- L (consonant): 12
- E (vowel): 5x2=10
So, code becomes: 6 42 20 18 12 10 ? 64220181210
Let’s check the options:
1. 64220091205
2. 64220181210
3. 62120091210
4. 62220181310
Option 2 is correct.
Here’s what this really means:
- The rule is vowels get doubled in their alphabet position, consonants don’t.
- Each option is just mixing around possible placements or making mistakes in the math.
- Option 2 matches the logic 100%. That’s why it’s the answer.
By: santosh ProfileResourcesReport error
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