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Dheeraj can cover a certain distance in 5 hours and 22 minutes by covering three-fourth of the distance at 5 km/h and rest at 6
km/h.Find the total distance covered by him.
28km/h
30km/h
25km/h
26km/h
- The total travel time is 5 hours and 22 minutes, which is equal to 5.3667 hours.
- Define the total distance as \(D\).
- \( \frac{3}{4} \) of the distance is covered at 5 km/h: \( \frac{3}{4}D = 5t_1 \) where \( t_1 \) is the time taken.
- \( \frac{1}{4} \) of the distance is covered at 6 km/h: \( \frac{1}{4}D = 6t_2 \) where \( t_2 \) is the time taken.
- The total time is \( t_1 + t_2 = 5.3667 \).
Solve equations:
- \( t_1 = \frac{3D}{20} \)
- \( t_2 = \frac{D}{24} \)
Plug in \( t_1 + t_2 = 5.3667 \):
- \( \frac{3D}{20} + \frac{D}{24} = 5.3667 \)
- Solve for \( D \) to get 26 km.
- Option 1: 28 km/h
- Option 2: 30 km/h
- Option 3: 25 km/h
- Option 4: 26 km/h
By: santosh ProfileResourcesReport error
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