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Among six objects F, G, H, J, K and L:
i. H is twice as heavy as K, and J is one and half times as heavy as F.
ii. G is half as heavy as J.
iii. F and J together are less heavy than H.
iv. J and L together are twice as heavy as F.
If the objects are arranged in descending order of their weight, which object will be second from the bottom?
K
L
F
G
- Statement i: H = 2K, J = 1.5F
- Statement ii: G = 0.5J
- Statement iii: F + J < H
- Statement iv: J + L = 2F
Calculating relationships:
- From ii, G = 0.5J = 0.5 * 1.5F = 0.75F
- From iv, J + L = 2F implies L = 2F - J
Given these conditions:
- H = 2K, F, and K are the lightest because H is heavier than their sum.
- G = 0.75F, lighter than J, who is 1.5F.
When ordered from heaviest to lightest, the sequence is H, J, L, F, G, K. Therefore, the second from the bottom is G.
Answer: Option 4 - G
.
By: santosh ProfileResourcesReport error
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