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Let x be the least number between 56,000 and 60,000 which when divided by 40, 45, 50 and 55 leaves a remainder of 23 in each case. What is the sum of the digits of x ?
23
21
26
19
Correct option 1: 23
LCM (40, 45, 50, 55) = 19800 19800K + 23 Let k = 3, 19800 x 3 + 23 = 59400 + 23 = 59423 Therefore, sum of digits of x = 5 +9+4+2+3=23
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