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A man is driving to his workplace at five-eighths of his usual speed, He reaches his workplace 36 minutes late, What is his
usual time (in hours) of travel?
1
2.5
2
1.5
- The man is driving at five-eighths of his usual speed. This means he is slower than his normal pace.
- Because of this reduced speed, he reaches his workplace 36 minutes later than usual.
- Let's denote his usual time of travel as \( t \).
- At his usual speed, he covers the distance in \( t \) hours.
- At five-eighths of his usual speed, it takes him \( \frac{8}{5} t \) hours to cover the same distance.
- The difference in time because of the reduced speed is \( \frac{8}{5} t - t = \frac{3}{5} t \), and this equals 36 minutes, which is 0.6 hours.
- Solving \( \frac{3}{5} t = 0.6 \) gives \( t = 1 \) hour.
- Option: 1 - 1 hour: Correct, as calculated above.
- Option: 2 - 2.5 hours: Incorrect, the time is not that long.
- Option: 3 - 2 hours: Incorrect, doesn't match the calculation.
- Option: 4 - 1.5 hours: Incorrect, slightly longer than calculated time.
By: santosh ProfileResourcesReport error
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