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Which is the largest number that divides 827, 1149 and 1310 to leave the same remainder in each case?
161
116
232
322
- To find the largest number that leaves the same remainder when dividing 827, 1149, and 1310, we need to find the greatest common divisor (GCD) of their pairwise differences.
- Calculate differences:
- 1149 - 827 = 322
- 1310 - 1149 = 161
- 1310 - 827 = 483
- Find the GCD of these differences (322, 161, 483).
- The GCD of 322 and 483 is 161.
- The GCD of 161 and 161 is 161.
- Therefore, the largest number is 161.
- Option:1 161 is the correct answer.
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