Multiple Choice Questions

If the length of a rectangle is increased by 40 what would be the percentage decrease correct to one...........

Quantitative Aptitude (MTS) Mensuration 2D

If the length of a rectangle is increased by 40%, what would be the percentage decrease ( correct to one place of decimal) in the

width to maintain the same area?

This questions was previously asked in

SSC MTS 7th October 2021 Shift-3

37.5%

33.5%

28.6%

42.5%

To solve this, let's work through it step by step:

- The area of a rectangle is given by multiplying the length by the width.

- When the length increases by 40%, its new length is 1.4 times the original. To keep the area the same, the width must decrease.

- Let the original width be W. The new width must multiply with the new length to equal the original area: 1.4 * L * new width = L * W.

- By simplifying, new width = W / 1.4.

- The percentage decrease in width = [(W - (W / 1.4)) / W] * 100% = (1 - 1/1.4) * 100%.

- This equals approximately 28.6%.

The correct option is:

- Option 3: 28.6%

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