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The total number of students in class A and B is 92. The number of students in A is 30% more than that in B. The average
weight (in kg) of students in B is 50% more than that of students in A. If the average weight of all the students in A and B is 56
kg, then what is the average weight (in kg) of students in B?
46
40
69
52
Given Total number of students in class A and B = 92 Number of students in class A = Number of students in class B + 30% of the number of students in class B Average weight of students of class A and B = 56 Average weight of students of class B = Average weight of students of class A+ 50% of average weight of students class A Concept Combined meanXAB = [(number of students in class A x Average weight of student of class A) + (number of students in class B x Average weight of student of class B)/(Total number of students in class A and B) Calculation A+B=92 A =B + 30% of B A 1308/100 =A=130 (92-A)/100 =A=(11960-130A)/100 100A = 11960-130A =230A = 11960 =A=52 B=92-52 =40 Let the average weight of students of section A = x Average weight of students of sectionB = x + 50% of x =150x/100 56 = 52xx+40 x 1.5x)/92 56 x 92 52x+60x =5152 = 112x ⇒x=5152/112 ⇒x=46 B = x + 50% of 46 =46 +23 =69 The average weight (in kg) of students in B le 69.
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