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The dimensions of a solid metallic cuboid are 36 cm, 54 cm and 24 cm. It is melted and recast into 8 cubes of same volume.
The sum of the surface areas (in cm2 ) of these 8 cubes is:
10368
11664
9720
15552
- The volume of the cuboid is calculated by multiplying its dimensions: \(36 \times 54 \times 24 = 46,656 \, \text{cm}^3\).
- This cuboid is melted and recast into 8 cubes of equal volume.
- The volume of one cube is thus \(46,656 \div 8 = 5,832 \, \text{cm}^3\).
- The side length of one cube is the cube root of 5,832, which is 18 cm.
- The surface area of one cube is calculated as \(6 \times (\text{side length})^2 = 6 \times 18^2 = 1,944 \, \text{cm}^2\).
- For 8 such cubes, the total surface area is \(8 \times 1,944 = 15,552 \, \text{cm}^2\).
Option 4: 15,552 is correct. .
By: santosh ProfileResourcesReport error
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