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A school has 100 students and every student plays either cricket or football or both, Thenumber of students who play cricket is twice the number of students who play football. Also, the number of students who play only cricket is three times the number of students who play only football. The number of students who play both cricket and football is, therefore :
30
28
25
20
- Let's define variables: Let C be the number of cricket players and F be the number of football players. B is the number of students playing both sports.
- We know all students play either or both sports: C+F−B=100.
- The school states C=2F, meaning twice as many students play cricket as football.
- It's given that students playing only cricket are three times those playing only football. So, C−B=3(F−B).
- Simplifying:
- Replace C with 2F: 2F−B=3(F−B).
- This simplifies to 2F−B=3F−3B, which leads to F=2B.
- Substituting back:
- C+F−B=100 becomes 2F+F−B=100 and F=2B.
- So, 3B+2B−B=100 leads to 4B=100, giving B=20.
Thus:
- The number of students playing both sports is 20.
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