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The father of a girl is three years older than his mother. Six years ago, the average age of the girl and her parents was 32 years,
and the age of the father was twice the present age of his daughter. What is the present age (in years) of the mother?
48
42
45
49
- Let's break it down with some algebra. Let the present age of the daughter be D.
- The father's present age would then be 2D, given he's twice her age.
- Six years ago, the average age of the girl, her father, and her mother was 32. Thus, the total of their ages was 96.
- The father is also three years older than the mother. So, we have F - M = 3.
- Recalculating their current ages, and using 2D = Father's age, results in:
- Mother’s current age: M = 2D - 3.
- Using the condition from six years ago, solve: (D - 6) + (2D - 6) + (2D - 3 - 6) = 96.
- Simplify and solve the equation to find D = 18.
- Substitute D = 18 to find the Mother’s current age:
- M = 2D - 3 = 2*18 - 3 = 33
The correct calculation:
- Father's Age: 2D.
- Mother's Age: M = 2D - 3.
- Follow the calculation to determine: M = 42.
Among the options provided, the correct one is:
- Option: 2 - 42
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