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Two trains of the same length are running on parallel tracks in the same direction at 44 km/h and 32 km/hr. The faster train
passes the other train in 72 seconds. What is the sum of the lengths (in m) of both the trains?
240
200
190
250
- The problem specifies two trains running in the same direction at different speeds.
- Speed difference between trains: \(44 \text{ km/h} - 32 \text{ km/h} = 12 \text{ km/h}\).
- Convert this relative speed to meters per second:
$$12 \text{ km/h} \times \frac{1000}{3600} = \frac{12000}{3600} \approx 3.33 \text{ m/s}$$.
- The faster train overtakes the slower one in 72 seconds.
- The distance covered in this time is given by:
$$3.33 \text{ m/s} \times 72 \text{ s} = 240 \text{ meters}$$.
- Therefore, the sum of the lengths of the trains is 240 meters.
Option 1: 240 is the correct answer.
By: santosh ProfileResourcesReport error
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