The area of a trapezium whose parallel sides are 25 cm and 19 cm long is 330 cm2 The distance b...........

Quantitative Aptitude (MTS) Geometry

The area of a trapezium, whose parallel sides are 25 cm and 19 cm long, is 330 cm². The distance between the sides (in cm) is:

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SSC MTS 2nd Nov 2021 Shift-2

To find the distance between the parallel sides of a trapezium, you can use the formula for the area of a trapezium:

- Formula: Area = \( \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height} \).

- Given values:

- Base_1 = 25 cm

- Base_2 = 19 cm

- Area = 330 cm²

- Plug the values into the formula:

- \( 330 = \frac{1}{2} \times (25 + 19) \times \text{Height} \).

- Solve for Height:

- \( 330 = \frac{1}{2} \times 44 \times \text{Height} \).

- \( 330 = 22 \times \text{Height} \).

- Height = 330 ÷ 22 = 15 cm.

- Option 4: 15 cm is the correct answer.

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