Ranbir bought a car at a 50 discount on the cost price of the car Had he got a 60 discount he would ...........

Quantitative Aptitude (MTS) Profit and loss

Ranbir bought a car at a 50% discount on the cost price of the car. Had he got a 60% discount, he would have spent Rs1,00,000

less. Calculate the cost price of the car?

This questions was previously asked in

SSC MTS 5th July 2022 Shift-3

Rs15 lakhs

Rs20 lakhs

Rs18 lakhs

Rs10 lakhs

- Ranbir got a 50% discount on the cost price of the car.

- He thought of a scenario where he could have received a 60% discount.

- The difference in discounts would save him Rs 1,00,000.

- Let's denote the cost price of the car as Rs X.

- A 50% discount means he paid 50% of X: \(0.5 \times X\).

- A 60% discount would mean paying 40% of X: \(0.4 \times X\).

- The difference in these two amounts is Rs 1,00,000: \((0.5X - 0.4X) = 1,00,000\).

- Therefore, \(0.1X = 1,00,000\).

- Solving for X gives \(X = 10,00,000\) or Rs 10 lakh.

Option:4, Rs10 lakhs

Submit Error