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The average of 12 numbers is M and the average of 8 of these numbers is P. If the average of remaining numbers is then which
of the following options is correct?
3M = 2P + N
4M = 2P + 3N
6M = 3P + 2N
6M = 2P + 3N
- You have 12 numbers with an average of M.
- The sum of all 12 numbers is 12M.
- For 8 of those numbers, the average is P.
- The sum of those 8 numbers is 8P.
- The remaining 4 numbers then have a sum of 12M−8P.
- If the average of these 4 numbers is N, then their sum is 4N.
- Thus, we have the equation 12M−8P=4N.
- Dividing the whole equation by 4 gives 3M−2P=N, which can be rearranged to 3M=2P+N.
Option 1: 3M = 2P + N
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