Multiple Choice Questions

Points P and Q are 400 km apart A person starts from P towards Q at 6 a m at a speed of 20 km h Anot...........

Quantitative Aptitude (MTS) Time & distance

Points P and Q are 400 km apart. A person starts from P towards Q at 6 a.m. at a speed of 20 km/h. Another person starts from

Q towards Pat 6:30 a.m. at a speed of 30 km/h. At what time will they meet?

This questions was previously asked in

SSC MTS 20th July 2022 Shift-1

1:48 p.m

2:18 p.m

1:38 p.m

2:28 p.m

- Two persons start moving towards each other from points P and Q.

- The distance between P and Q is 400 km.

- The first person leaves point P at 6 a.m., traveling at 20 km/h.

- The second person leaves point Q at 6:30 a.m., traveling at 30 km/h.

- Calculate the time they meet:

- By 6:30 a.m., the first person has already traveled 10 km (20 km/h * 0.5 hours).

- The remaining distance is 390 km (400 km - 10 km).

- Their combined speed is 50 km/h (20 km/h + 30 km/h).

- Time to meet is 390 km ÷ 50 km/h = 7.8 hours.

- 7.8 hours after 6:30 a.m. is 2:18 p.m.

- Correct Answer: Option 2, 2:18 p.m.

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