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How much iron sheet (in m2 ) will be needed to construct a rectangular tank measuring 10 m x 8 m x 6 m, if a circular opening
of radius one meter is to be left at the top of the tank? (correct to one decimal place)
370.4
370.8
372.9
371.6
To determine how much iron sheet is needed to construct the tank, consider these points:
- Surface Area Calculation:
- The tank is a rectangular prism with dimensions 10 m x 8 m x 6 m.
- Calculate the surface area:
- Two sides of 10 m x 6 m each: 2×10×6=120 m²
- Two sides of 8 m x 6 m each: 2×8×6=96 m²
- The bottom of 10 m x 8 m: 10×8=80 m²
- Circular Opening:
- The circular opening has a radius of 1 m.
- Calculate the area: π×12=3.14 m² (use π≈3.14)
- Total Iron Sheet Area:
- Total surface area without top: 120+96+80=296 m²
- Add the top (excluding the circular opening): 10×8−3.14=76.86 m²
- Total iron sheet = 296+76.86=372.86 m²
- Rounded Calculation:
- Round 372.86 to one decimal: 372.9 m²
Option 3: 372.9 is the correct choice.
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