In ABC F and E are the points on sides AB and AC respectively such that FE BC and FE divides th...........

Quantitative Aptitude (CGL) Geometry

In $\bigtriangleup$ ABC, F and E are the points on sides AB and AC. respectively, such that FE $\parallel$ BC and FE divides the triangle in two parts of

equal area. If AD $\perp$ BC and AD intersects FE at G, then GD : AG = ?

This questions was previously asked in

SSC CGL 4 June 2019 Shift-1

View All ssc Previous Year Papers

$\sqrt{2}:1$

$(\sqrt{2}-1):1$

$2\sqrt{2}:1$

$(\sqrt{2}+1):1$

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Explanation:

It is given that FE divides $\bigtriangleup$ ABC, into two equal parts.

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In ABC F and E are the points on sides AB and AC respectively such that FE BC and FE divides th...........

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Explanation:

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