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Multiple Choice Questions

A thief is spotted by a policeman from a distance of 250m When the policeman starts the chase the th...........

Quantitative Aptitude (CPO) Time & distance

A thief is spotted by a policeman from a distance of 250m. When the policeman starts the chase, the thief also starts running.

Assuming that the speed of the thief is 10 km/h and that of the policeman is 12 km/h, how far would the thief have run before

he is caught?

This questions was previously asked in

SSC CPO 9th Nov 2022 Shift 1

View All SSCCPO Previous Year Papers

4 km

1.25 km

3 km

2 km

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Explanation:

1.25 km

- The scenario involves a policeman chasing a thief, both starting at the same moment.
- The distance between them initially is 250 meters.
- The thief runs at a speed of 10 km/h.
- The policeman runs faster, at 12 km/h.
- We need to find out how far the thief runs before being caught.
- The relative speed between the policeman and the thief is 2 km/h (12 km/h - 10 km/h).
- To close the 250-meter gap at a relative speed of 2 km/h, the time taken is 0.125 hours (since 250 meters is 0.25 km, and time = distance/speed).
- During this time, the thief runs a distance of 1.25 km (at 10 km/h for 0.125 hours).

**✅ Correct Answer: Option 2 - 1.25 km**

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