Explanation:

- Let's break down the problem statement:

- A is greater than B by 7: So, $A=B+7$.

- B is greater than C by 16: So, $B=C+16$.

- The sum of A + B + C is 255: $A+B+C=255$.

- Substitute the equations:

- Replace $A$ with $B+7$ and $B$ with $C+16$ in the equation $A+B+C=255$:

$(B+7)+B+(B-16)=255$

$(B+7)+B+C=255$

- Simplifying, we get $B=79$, $A=86$, and $C=63$.

- Find $3A+C-4B$:

- $3A=258$

- $4B=316$

- $258+63-316=5$

- Option 1: 5