A faulty weighing machine reads 1 kg when 900 gm is actually weighted on it The shopkeeper marked th...........

Quantitative Aptitude (CPO) Profit and loss

A faulty weighing machine reads 1 kg when 900 gm is actually weighted on it. The shopkeeper marked the price of his goods by

10%, but unfortunately he was caught by the metrology department and then they ordered him to repair his weighing machine

and gave punishment to sell the goods at 10% discount on cost price for a month. If each customer is now paying Rs20 for 1 kg,

then before the raid _______ amount they have paid for the same quantity. (Rounded off to two places of decimal)

This questions was previously asked in

SSC CPO 9th Nov 2022 Shift 1

Rs27.16

Rs27.04

Rs28.05

Rs28.15

- The faulty weighing machine shows 1 kg instead of 900 gm. Therefore, when customers pay for 1 kg, they actually receive only 900 gm.

- The shopkeeper marked the price by 10% above cost price.

- After repairing the machine, he sold 1 kg for Rs20 with a 10% discount on the cost price.

- Since 900 gm was sold as 1 kg before the raid, the payment would be more because 100 gm less was sold.

- To find the original price paid for 1 kg (pre-raid), calculate the price when 900 gm was sold as 1 kg considering the marked pricing.

- Pre-raid payment calculation:

- Original cost (900 gm) = Rs 20 / 0.9 (10% discounted price for 1 kg now).

- Actual price for 900 gm post-repair = 20 / 0.9 = Rs 22.22.

- With 10% mark-up before the raid, price = Rs 22.22 * 1.1 = Rs 24.44 for 900 gm.

- Price for actual 1 kg = Rs 24.44 / 0.9 = Rs 27.16.

- Option 1: Rs 27.16 is correct.

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