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If 3 sec2 θ + tan θ − 7 = 0, 0° < θ < 90°,then what is the value of
2 sin θ+3cosθ
10
5
4 /2
Let’s break it down step by step:
- Start with the given equation:
3 sec²? + tan? – 7 = 0
Replace sec²? with 1 + tan²?:
- 3(1 + tan²?) + tan? – 7 = 0
? 3 + 3tan²? + tan? – 7 = 0
? 3tan²? + tan? – 4 = 0
- Factor: (3tan? – 4)(tan? + 1) = 0
- ? ? (0°, 90°), so tan? = 4/3 (Since tan? = –1 doesn't fit in this range.)
- Now, use right triangle ratios:
- If tan? = 4/3,
- Opposite/Adjacent = 4/3
- Hypotenuse = v(3²+4²) = 5
- sin? = 4/5,
- cos? = 3/5
- Now answer the question: find
2sin? + 3cos? / (cosec? + sec?)
- 2sin? + 3cos? = 2(4/5) + 3(3/5) = (8+9)/5 = 17/5
- cosec? = 1/sin? = 5/4; sec? = 1/cos? = 5/3
So, cosec? + sec? = 5/4 + 5/3 = (15+20)/12 = 35/12
- The expression is:
(17/5) ÷ (35/12) = (17/5) × (12/35) = (17×12)/(5×35) = 204/175
Let’s check the options:
- Option 1: 10
- Option 2: 5
- Option 3: 5
- Option 4: 4/2
None of these match exactly, from 204/175 ˜ 1.17.
It looks like the options are suspicious or perhaps the question was miswritten or rounding expected.
But if your answer was option 3: 5, let’s compare:
- 2sin? + 3cos? = 17/5
- Denominator is 35/12
- Quotient: (17/5)/(35/12) = 204/175 ? 5
If you want me to clarify any step or re-check with a particular assumption, let me know!
By: Parvesh Mehta ProfileResourcesReport error
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