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Reema starts from her house and cycles 4 km towards the west and then turns right and cycles 6 km. She again turns right and
cycles for X km to reach her school. Point A is to the south of her school and also 2 km to the west of her house. What is the
value of X?
6 km
8 km
2 km
4 km
Let’s walk through this together:
- Reema starts at her house, heads 4 km west.
- She turns right (which means she’s now facing north) and cycles 6 km.
- She turns right again (now facing east) and cycles X km. This gets her to school.
- So, let’s see: her total westward movement was 4 km, and now she’s moving back east for X km. If X was also 4 km, she’d be directly north of her starting point.
- Now, there's more: Point A is south of her school and 2 km west of her house.
- If her school was straight north after moving west, there’d be no extra “east” needed. But since Point A is specifically 2 km west of the house, her school is not directly in line.
- So, her house to Point A is 2 km west, and the path back from school is eastward.
- To get from 4 km west to 2 km west (relative to her house), she needs to go east 2 km — that’s X.
So out of the options:
Option 1: 6 km – way too far, that would take her past her original start point.
Option 2: 8 km – even further east, not right.
Option 3: 2 km – exactly the point, this lines up school with 2 km west of the house.
Option 4: 4 km – that would put school aligned with her house, not 2 km to the west.
Option 3: 2 km is the correct answer.
By: santosh ProfileResourcesReport error
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