Explanation:

- Ramesh travels at 40 km/h and is 25 minutes late, and the next day at 50 km/h, he is only 10 minutes late.

- Let's denote the actual time Ramesh should take to reach college as $t$.

- The first day, the time taken is $\frac{d}{40}=t+\frac{25}{60}$.

- The second day, the time taken is $\frac{d}{50}=t+\frac{10}{60}$.

- Solving these equations:

$$\frac{d}{40}-\frac{d}{50}=\frac{25}{60}-\frac{10}{60}$$

$$\frac{5d}{2000}=\frac{15}{60}$$

$$d=50\text{km}$$

- Correct Option: $$ Option 1: 50 km