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A trader bought twoarticles for Rs490. Hesold one at a loss of 20% and the other at a profit of 16%.If the selling price of both
articles is same, then the cost price (in Rs) of the article sold at 20% loss is:
310
300
290
280
- Let the cost price of the article sold at 20% loss be Rs. x.
- The cost price of the other article is Rs. (490 - x).
- Selling price of article 1 (20% loss) = x × 0.8
- Selling price of article 2 (16% profit) = (490 - x) × 1.16
- The SPs are the same. Set them equal:
x × 0.8 = (490 - x) × 1.16
- Solve:
0.8x = 1.16×490 - 1.16x
0.8x + 1.16x = 1.16×490
1.96x = 568.4
x = 568.4 / 1.96 = 290
- So, the cost price is Rs. 290.
- Option:1, 310
- Option:2, 300
- Option:3, 290
- Option:4, 280
Correct Answer:
Option:3, 290
By: santosh ProfileResourcesReport error
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