The distance between two stations A and B is 428 km A train starts from station lsquo A rsquo at 6 0...........

Quantitative Aptitude (CGL) Problems on trains

The distance between two stations, A and B, is 428 km.A train starts from station ‘A’ at 6:00 a.m. and moves towards station ‘B’

at an average speed of 48 km/h. Another train starts from station ‘B’ at 6:20 a.m. and moves towards station ‘A’ at an average

speed of 55 km/h. At what time will the trains meet?

This questions was previously asked in

SSC CGL 5th March 2020 Shift-3

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10 : 20 a.m.

9 : 40 a.m.

10 : 40 a.m.

10:00 a.m.

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Explanation:

Distance from A to B = 428 km
Speed of train A = 48 km/hr
Speed of train B = 55 km/hr
Train A starts at 6:00 am and B start at 6:20 so,
Distance covered by by train A in 20 min(20/60 hr) = speed $$\times (20/60) = 48 \times (1/3) = 16 km
Remaining distance = 428 - 16 = 412 km
Trains run in opposite direction so relative speed = 48 + 55 = 103 km/hr
Time taken to meet = 412/103 = 4 hr
Time when trains meet = 6:20 + 4 = 10:20 am

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